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You put a bottle of soft drink in a refrigerator and leave it until its temperature has dropped 10.0 K. What is its temperature change in (a) F$^\circ$ and (b) C$^\circ$?

(a) $\Delta T_{\mathrm{F}}=\frac{9}{5} \Delta T_{\mathrm{C}}=\frac{9}{5}\left(-10.0 \mathrm{C}^{\circ}\right)=-18.0 \mathrm{F}^{\circ}$

(b) $\Delta T_{\mathrm{C}}=\Delta T_{\mathrm{K}}=-10.0 \mathrm{C}^{\circ}$

Temperature and Heat

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Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

McMaster University

So here we have a change in temperature for of negative 10 Calvin and we know to change from Fahrenheit. Brothers changed himself. Sees two Fahrenheit. It would be the temperature and Fahrenheit equaling 9/5 times the temperature in Celsius plus 32 for the temperature and Calvin. It'll simply be the temperature and Celsius plus 273. So for party when they want the change in temperature for into in Fahrenheit, we can say that the change in temperature would be equal to 9/5. The change in temperature and Calvin and so the change in temperature would be equal to native 18 degrees Fahrenheit and then for part B when they want us to express it in county in Celsius, the change in temperature would simply be negative 10 degrees Celsius because the converting from Celsius is Calvin is simply just adding 273. So when we take the change in temperature, the 2 73 cancels out, of course, and the change in temperature and Kelvin will be equal to the change in temperature and Celsius. That is the end of the solution. Thank you for watching

Carnegie Mellon University

Temperature and Heat