00:01
We must determine the moles of hydrogen ion we have in the solution therefore moles of h3o plus is 36 .78 milliliter converted to liter then to moles of hcl and then moles of hydrogen ion in one mole of hcl that is 3 .86 multiplied by 10 to the per minus 4 moles now equal the numbers of moles base and acid defines the equivalence point thus we know that we must have the same number of ammonia in solution as we added hydrogenium ion now let us determine the concentration of ammonia there is nh3 is equal to 3 .86 multiplied by 10 to the power minus 4 mole upon 0 .025 layers that is 1 .54 multiplied by 10 to the power minus 2.
01:40
Therefore the concentration of ammonia is 1 .54 into 10 to the power minus 2 mold.
01:55
Second, we know that adding the hydrogen ion to ammonia will make the following reaction.
02:07
There is nh3 aquas plus h3o plus aquas forms nh4 plus h2.
02:27
Now let us make the ice table to determine the changes in amund.
02:34
Amount of amount moles of each species when we titrate.
02:39
There is the initial, then the change and the final.
02:50
Nh3, h3o plus forms the nh4 ion plus h2o.
03:05
Initially we have 3 .86 into 10 to the power minus 4.
03:13
3 then 3 .86 into 10 to the power minus 4, h3o, and h40, and h4 is minus 8 .6 into 10 to the power or minus 4, negative 3 .86 into 10 to the power minus 4, and h4 is 3 .86 into 10 to the power minus...