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You switch from a 1.40$N A 60 \times$ oil immersion objective to a 1.40$N A 60\times$ oil immersion objective. What are the acceptance angles for each? Compare and comment on the values. Which would you use first to locate the target area on your specimen?

$135^{\circ}$

Physics 103

Chapter 26

Vision and Optical Instruments

Reflection and Refraction of Light

Wave Optics

University of Washington

Simon Fraser University

University of Sheffield

McMaster University

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the relationship between all four and medical that torture is given by an aged in the medical approach of that is a book perfectly next sign ofa full hair physical to one for oil. So area for oil a physical 1.51 There we could find the first angle. Also, one is equal to sign in. Worse off, um, anything you want divided by affecting index off oil. So substituting the values here we get in a one we have is 1.4 divided by affecting this afford 1.51 But the writing these two numbers and taking assigning more schemes of 68 degrees here also two will be similarly using the same formula. And a two you worry about affecting rips off air here in substrate in the values start getting worse off um, 0.35 divided by one here for air. This gives us angle of 21 degrees, so also want he's 60 and also two is 21 We see here also to is smaller than over one. Therefore, second lens lenses would be useful for locating a target area because it will show less details over a larger area. Less detail, most larger area. Yeah,

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