00:01
In this question, we're trying to build a cyclotron which can accelerate protons to a speed of 3 times 10 to the 7 metres per second.
00:07
We also know that the largest magnetic field strength we can obtain is 1 .5 tesla's.
00:12
We want to find the minimum radius of the bs in our cyclotron and show how it comes from newton's second law.
00:18
So, what we can say is that in the cyclotron, when the magnetic field is perpendicular to the velocity, the magnetic force is given by b, which is the magnetic.
00:30
Field strength, q, the charge v.
00:35
Newton's second law for a circular motion is, say, it's that force is equal to mv squared over r, but r is the radius of the circular motion.
00:49
So what we can do is we can equate these two expressions.
00:52
We can say that bqv is equal to mv squared over r.
01:01
We can and then rearrange this expression in order to obtain r...