We can use the formula for power, which is given by $P = IV$, where $P$ is power, $I$ is current, and $V$ is voltage. Given that $P = 46 \times 10^6$ W and $V = 240 \times 10^3$ V, we can solve for $I$:
\[I = \frac{P}{V} = \frac{46 \times 10^6 \, \text{W}}{240
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