00:01
Okay, so for this question, the first thing that we need to do is we need to determine the amount of air within this house, right? so we can do that by the volume of air is equal to, so let's find the volume first.
00:19
So we have the area is 275 meters square, so volume is linked times width times height, right? so 275 meter square is the area that's already the link time width.
00:30
So now we have to multiply it by the height and they tell us it's 2 .5 meters right so this if we plug this into the calculator this will give us volume but let's convert this meters cube into liters right so i've written the conversion of meters cube to liters down here so one meters cube is equal to a thousand liters so we get the volume of error to be equal to 6 .88 times 10 to the 5 liters now the next thing we can do is we can convert the volume air to moles of air by using the density and the average molecular mass of the air.
01:13
So, moles, air is equal to 6 .88 times 10 to the 5 liters.
01:24
Right.
01:25
So they tell us the density of air is 1 .22 grams per liter.
01:31
And they also tell us the molar mass of air is 28 .9 grams per mo.
01:42
Right? so liters cancels out, grams cancels out, and we're left with moles of air.
01:48
And we get the answer to be 2 .9 times 10 to the 4 moles.
01:54
That is how many modes of air we have.
01:58
Now the next thing that we can do is determine how much heat, how much energy is needed to raise the temperature of air from 15 degrees celsius to 22 degrees celsius.
02:10
So i've converted the celsius into kelvin's.
02:12
All you've got to do is add 273, right? so it's 288 for the 15 degrees celsius and 295 for the 22 degrees celsius.
02:21
And the equation that we need to use to determine how much energy is needed is q is equal to m -c -delta -t, right? so q is equal to m.
02:33
So what is the m? so m we have 2 .9 times 10 to the 4 moes.
02:46
Now for c they tell us it's 29 .1 joules per mole.
02:52
So 29 .1 joules per mole.
02:58
Right, so this m can be in the units of moes or in the units of grams, depending on what the c is.
03:06
And since our c is jewels per moz, we leave it in most.
03:09
If it was joules per grams, then we would need to convert this moles into grams.
03:15
Okay, so, oops, now for the delta t.
03:20
Delta t is t final minus t initial, right? so 295 kelvin minus 288 kelvin...