We can use the formula for power, $P = \frac{V^2}{R}$, to find the resistance, $R = \frac{V^2}{P}$.
For the headlight, we have:
\[R_{headlight} = \frac{V^2}{P_{headlight}} = \frac{(12.0V)^2}{30.0W} = 4.8 \, \Omega\]
For the starter, we have:
\[R_{starter} =
Show more…