You're $1.44 \mathrm{~m}$ from a charge distribution that is well under $1 \mathrm{~cm}$ in size. You measure an electric field strength of 296 N/C due to this distribution. You then move to a distance of $2.16 \mathrm{~m}$ from the distribution, where you measure a field strength of $87.7 \mathrm{~N} / \mathrm{C}$. What's the net charge of the distribution? Hint: Don't try to calculate the charge. Determine instead how the field decreases with distance, and from that infer the charge.