The Laplace transform of the left side is $s^2Y(s)-sy(0)-y'(0)+2sY(s)-2y(0)+2Y(s)$ and the Laplace transform of the right side is $e^{-\pi s}$. Substitute the initial conditions $y(0)=1$ and $y'(0)=1$ into the equation, we get
$$s^2Y(s)-s-1+2sY(s)-2+2Y(s)=e^{-\pi
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