Question
Zinc and sulfur react to form zinc sulfide, ZnS . If we mix 19.5 g of zinc and 9.40 g of sulfur, have we added sufficient sulfur to fully react all the zinc? Show evidence for your answer.
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The balanced equation is: \[ \text{Zn} + \text{S} \rightarrow \text{ZnS} \] Show more…
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Zinc and sulfur react to form zinc sulfide according to the equation: Zn + S → ZnS. If 100.0 g of zinc and 30.0 g of sulfur are mixed, fill in the blanks using the options provided: a) Which is the limiting reactant? Options: Zn, S, ZnS, none of the above b) How many grams of ZnS will be formed? Options: 0.9383, 0.3891 c) How many moles of the excess reactant will remain after the reaction is over? Options: 0.28, 0.59, 0.93839
The element zinc reacts with the element sulfur to form a white solid compound, zinc sulfide. When a sample of zinc that weighs $65.4 \mathrm{~g}$ reacts with sulfur, it is found that the zinc sulfide produced weighs exactly $97.5 \mathrm{~g}$. (a) Calculate the mass of sulfur in the zinc sulfide. (b) Calculate the mass of zinc sulfide that could be produced from $20.0 \mathrm{~g}$ zinc.
The element zinc reacts with the element sulfur to form a white solid compound, zinc sulfide. When a sample of zinc that weighs $65.4 \mathrm{~g}$ reacts with sulfur, it is found that the zinc sulfide produced weighs exactly $97.5 \mathrm{~g}$. (a) What mass of sulfur is present in the zinc sulfide? (b) What mass of zinc sulfide could be produced from $20.0 \mathrm{~g}$ zinc?
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