00:01
The first part of this question is to calculate the molar solubility of zinc hydroxide in pure water.
00:07
So we can do this simply knowing the ksp for zinc hydroxide.
00:14
Because zinc hydroxide solid will go to zinc 2 plus and the ksp is simply the concentration.
00:41
And the zinc is s equal to s, the molar solubus.
00:48
Ability to 2 s.
00:54
So the ksp for zinc hydroxide, which is 4 .1 times 10 to the negative 17, will be equal to s and 2s squared for 4 s cubed.
01:14
So our s then becomes 4 .1 to the negative 17 divided by 4 and then we take the cube root.
01:24
Of that is 2 .1 times 10 to the negative 6 molar.
01:36
It then asks us to calculate the ph of the solution and it turns out that the ph can be calculated from the hydroxide concentration or the hydroxide concentration is equal to 2s or with that being s 4 .34 times 10 to the negative 6 molar, and then ph is equal to the negative log of the hydronium concentration, h3o plus, which we can get from the hydroxide by dividing it into kw, and we get, divide those two, make the negative log 8 .64.
02:42
Now, to know the molar solubility of the zinc, hydroxide in a solution that contains 0 .1 molar sodium hydroxide, where the hydroxide concentration then is equal to zero.
03:03
We need to consider the new equilibrium.
03:07
The zn hydroxide is now going to react with some additional hydroxide and create the zn for two minus and it turns out that the kf value for that is really large three well we'll figure out that k value in a minute kf value is z n2 plus that kf value is what's given at three times 10 and 15.
04:12
We also know that zn -oh2 solid has a ksp value that describes this process.
04:30
Asp is equal to what was given up above 4 .1 times 10 by negative 17.
04:39
So how can we combine these two equations in order to get the above the above? equation here? well, it looks like if we simply add the two equations together, the zincs will cancel, two of the hydroxides will cancel, and we'll end up getting that reaction up there.
05:11
So the k value for this process then is just the product of those two k values shown below, 4 .1 negative 17 and the 3 times 10 to the 15...