A parallel plate electric field has its plates separated by 5.33 mm. If 600 V of potential difference exists between the plates, calculate: (a) the magnitude of the E-Field between the plates.
Correct answer:
1.13E5 N/C
(b) the magnitude of the force on an e- between the plates.
Correct answer:
1.80E-14 N
(c) how much work must be done on the e- to move it to the negative plate if it is initially positioned 2.90 mm from the positive plate.