Ace - AI Tutor
Ask Our Educators
Textbooks
My Library
Flashcards
Scribe - AI Notes
Notes & Exams
Download App

Divider

Viewed Questions

A toroidal solenoid has a mean radius $r$ and a crosssectional area $A$ and is wound uniformly with $N_{1}$ turns. A second toroidal solenoid with $N_{2}$ turns is wound uniformly around the first. The two coils are wound in the same direction. (a) Derive an expression for the inductance $L_{1}$ when only the first coil is used and an expression for $L_{2}$ when only the second coil is used.
(b) Show that $M^{2}=L_{1} L_{2}$

A toroidal solenoid has a mean radius $r$ and a crosssectional area $A$ and is wound uniformly with $N_{1}$ turns. A second toroidal solenoid with $N_{2}$ turns is wound uniformly around the first. The two coils are wound in the same direction. (a) Derive an expression for the inductance $L_{1}$ when only the first coil is used and an expression for $L_{2}$ when only the second coil is used. (b) Show that $M^{2}=L_{1} L_{2}$

University Physics with Modern Physics

A roast turkey is taken from an oven when its temperature has reached $ 185^{\circ}F $ and is placed on a table in a room where the temperature is $ 75^{\circ}F $. The graph shows how the temperature of the turkey decreases and eventually approaches room temperature. By measuring the slope of the tangent, estimate the rate of change of the temperature after an hour.

A roast turkey is taken from an oven when its temperature has reached $ 185^{\circ}F $ and is placed on a table in a room where the temperature is $ 75^{\circ}F $. The graph shows how the temperature of the turkey decreases and eventually approaches room temperature. By measuring the slope of the tangent, estimate the rate of change of the temperature after an hour.

Calculus: Early Transcendentals

Limits and Derivatives

Derivatives and Rates of Change

Questions asked

ANSWERED

Jenny Wu verified

Numerade educator

Conditional gene knockout is a popular approach in research involving mouse models. Often, loxP sites are inserted into the introns of a gene, say gene A, to create a floxed (fl) allele. Studies are often performed to mate mice with the Afl allele with another mouse stain containing a knock-in cre allele driven by gene B's promoter (referred to here as Bcre). Imagine that you hope to conduct experiments to define the phenotypes of mice with gene A knocked out in cells expressing gene B. Therefore, you obtained the Afl/flBcre/+ mice. In this nomenclature, fl/fl indicates that both gene A alleles are floxed. cre/+ means one of the gene B alleles contains cre, whereas the other allele is wildtype (wt, indicated by the + sign). Please describe (1) what are the genotypes for control mice that you have seen in the literature that the phenotypes of the Afl/flBcre/+ mice can be compared to? If there are more than two control genotypes that you have seen, you only need to list two of them. (2) For each of the genotypes in (1), what is the control genotype controlling for? What are the pros and cons? (3) In the ideal world (meaning you do not have to worry about the cost, labor, and the duration of the project), what genotype(s) are needed to convincingly demonstrate that the phenotypes of the Afl/flBcre/+ mice are due to the loss of gene A in cells expressing gene B? Please note that we assume that all mice and alleles are on the same pure genetic background (e.g. C57B6/J) and that backcrossing does not need to be considered.

View Answer
divider
INSTANT ANSWER

Conditional gene knockout is a popular approach in research involving mouse models. Often, loxP sites are inserted into the introns of a gene, say gene A, to create a floxed (fl) allele. Studies are often performed to mate mice with the \( A^{f l} \) allele with another mouse stain containing a knock-in cre allele driven by gene B's promoter (referred to here as \( B^{\text {cre }} \) ). Imagine that you hope to conduct experiments to define the phenotypes of mice with gene A knocked out in cells expressing gene B . Therefore, you obtained the \( A^{\text {f///F}} B^{\text {cre/t }} \) mice. In this nomenclature, fl/fl indicates that both gene A alleles are floxed. cre/+ means one of the gene \( B \) alleles contains cre, whereas the other allele is wildtype ( wt , indicated by the + sign). Please describe (1) what are the genotypes for control mice that you have seen in the literature that the phenotypes of the \( A^{\text {f// }} B^{\text {cre/t }} \) mice can be compared to? If there are more than two control genotypes that you have seen, you only need to list two of them. (2) For each of the genotypes in (1), what is the control genotype controlling for? What are the pros and cons? (3) In the ideal world (meaning you do not have to worry about the cost, labor, and the duration of the project), what genotype(s) are needed to convincingly demonstrate gene \( B \) ? Please note that we assume that all mice and alleles are on the same pure genetic background (e.g. C57B6/J) and that backcrossing does not need to be considered.

View Answer
divider
INSTANT ANSWER

Please refer to the Tang et al. paper (DOI: 10.1091/mbc.e09-09-0811) and answer the following questions. The screen used the following starting strain: TY2441 yls34 (Pxol-1::GFP+rol-6 (pRF4)). It will be helpful to know that ‘TY2441’ is just the name of this strain, and isn’t relevant to this THQ. ‘yIs34’ is the genotype. All the following information is just an explanation of what yIs34 is. Briefly, yIs34 is an allele where GFP has been inserted into the genome under control of the xol-1 promoter. xol-1 is only expressed in males. Thus, animals carrying yIs34 will express GFP if they are males, but not if they are hermaphrodites. Question :The authors isolated a mutant from the screen with a high incidence of spontaneous males. They used various methods to conclude that this mutant is a new allele of him-19. One method they used was to perform a complementation test against an existing allele of him-19, the allele him-19(tm3538). Draw out the crosses for this complementation test, using Punnet squares. Explain how they analyzed the results to conclude that the two alleles failed to complement and were likely alleles of the same gene.

View Answer
divider
ANSWERED

Jenny Wu verified

Numerade educator

Please refer to the Tang et al. paper (DOI: 10.1091/mbc.e09-09-0811) and answer the following questions. The screen used the following starting strain: TY2441 yls34 (Pxol-1::GFP+rol-6 (pRF4)). It will be helpful to know that ‘TY2441’ is just the name of this strain, and isn’t relevant to this THQ. ‘yIs34’ is the genotype. All the following information is just an explanation of what yIs34 is. Briefly, yIs34 is an allele where GFP has been inserted into the genome under control of the xol-1 promoter. xol-1 is only expressed in males. Thus, animals carrying yIs34 will express GFP if they are males, but not if they are hermaphrodites. Question : Give the complete genotype for the P0 generation and indicate what mutagen was used. Draw a Punnet square for the ‘cross’ that gives rise to the F1 generation

View Answer
divider
ANSWERED

Jenny Wu verified

Numerade educator

Please refer to the Tang et al. paper (DOI: 10.1091/mbc.e09-09-0811) and answer the following questions. The screen used the following starting strain: TY2441 yls34 (Pxol-1::GFP+rol-6 (pRF4)). It will be helpful to know that ‘TY2441’ is just the name of this strain, and isn’t relevant to this THQ. ‘yIs34’ is the genotype. All the following information is just an explanation of what yIs34 is. Briefly, yIs34 is an allele where GFP has been inserted into the genome under control of the xol-1 promoter. xol-1 is only expressed in males. Thus, animals carrying yIs34 will express GFP if they are males, but not if they are hermaphrodites. Question 1: In the screen, they did not look for males directly. What did they look for instead? Why do you think they chose to do this?

View Answer
divider
INSTANT ANSWER

What is the initial voltage drop over the boxed inductor?

View Answer
divider
INSTANT ANSWER

What is the eventual voltage drop over the boxed inductor, after a long period of time has passed?

View Answer
divider
INSTANT ANSWER

Draw the electric field due to an infinite plane of charge stacked above an infinite plane with charge density -2σ. Be sure to include the field in the space above the stack, between the two plates, and below the stack.

View Answer
divider
ANSWERED

Vishal Gupta verified

Numerade educator

If your patient were suffering from the focusing problem shown in the diagram below, would you provide them with a concave or convex lens to correct their vision?

View Answer
divider
ANSWERED

Nishant Kumar verified

Numerade educator

The Electric Field version of Gauss's Law is ( oint vec{E} cdot overrightarrow{d A}=frac{Q_{ ext {encl }}}{epsilon_{0}} ). What is the magnetic field version of Gauss's Law?

View Answer
divider