Solve the following equation for 𝜓.
1
a2
d2𝜓
d𝜑2
+
2𝜇
ℏ2
|E|𝜓 = 0,
Assume a standard trial solution
𝜓 = A exp(iB𝜑).
(Use the following as necessary: a, E, 𝜇, and ℏ.)
A =
B =
Find the allowed energies and angular momenta. (Use the following as necessary: a, 𝜇, ℏ, and n, the quantum number.)
E =
L =
Compare your results with the Bohr theory. (Select all that apply.)
These results are completely different from the Bohr theory.
The wave functions are the same as those of the Bohr theory.
The angular momenta are the same as those of the Bohr theory.
The energies are the same as those of the Bohr theory.