Viewed Questions
Use the matrix capabilities of a graphing utility to write the matrix in reduced row-echelon form . Use the matrix capabilities of a graphing utility to write the matrix in reduced row-echelon form. $$\left[\begin{array}{rrr} 3 & 3 & 3 \\ -1 & 0 & -4 \\ 2 & 4 & -2 \end{array}\right]$$
Linear Systems and Matrices
Matrices and Systems of Equations
Find the complex zeros of each quadratic function. Graph each function and label the intercepts. $f(x)=x^{2}-16$
Linear and Quadratic Functions
Complex Zeros of a Quadratic Function
Questions asked
Scott Stetson
Numerade educator
Enter a 3 !!! 3 skew-symmetric matrix A that has entries a21 = 1, a13 = 0, and a23 = 5. A = ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
(1 point) Enter a 3 x 3 symmetric matrix A that has entries a11 = 5, a22 = 1, a33 = 3, a12 = 4, a13 = 0, and a23 = 2. A = [ ]
(3 points) In each part, find the matrix \( X \) solving the given equation. a. \( \left[\begin{array}{cc}10 & 0 \\ 0 & 1\end{array}\right] X=\left[\begin{array}{cc}-3 & -5 \\ -2 & 1\end{array}\right] . X=[\square] \) b. \( \left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right] X=\left[\begin{array}{cc}-9 & 6 \\ 8 & -5\end{array}\right] . X=\left[\begin{array}{r}\square \\ \square\end{array}\right] \) c. \( \left[\begin{array}{ll}1 & 3 \\ 0 & 1\end{array}\right] X=\left[\begin{array}{cc}5 & -5 \\ -4 & 1\end{array}\right] . X=[\square] \) d. \( \left[\begin{array}{cc}1 & -4 \\ 6 & -23\end{array}\right] X=\left[\begin{array}{cc}-2 & 2 \\ -9 & -10\end{array}\right], X=[\square] \) e. \( \left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 10\end{array}\right] X=\left[\begin{array}{ccc}2 & 5 & -1 \\ -10 & 1 & -10 \\ -2 & 1 & 10\end{array}\right] \). f. \( \left[\begin{array}{lll}0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0\end{array}\right] X=\left[\begin{array}{ccc}-1 & 3 & 7 \\ -3 & -1 & 10 \\ -6 & -6 & 5\end{array}\right] \), \( X=\left[\begin{array}{l|l}\square \\ \square & \square\end{array}\right] \) g. \( \left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & -5 & 1\end{array}\right] X=\left[\begin{array}{ccc}-7 & -10 & -5 \\ -9 & 2 & -8 \\ -4 & -1 & 6\end{array}\right] \). \[ X=[\square] \square] \]
Shu Naito
(1 point) Consider the following two systems. (a) $$left{egin{array}{l}-4x - 5y = -3 \ -4x - 9y = -3end{array} ight.$$ (b) $$left{egin{array}{l}-4x - 5y = -1 \ -4x - 9y = -2end{array} ight.$$ (i) Find the inverse of the (common) coefficient matrix of the two systems. $$A^{-1} = egin{bmatrix} Box & Box \ Box & Box end{bmatrix}$$ (ii) Find the solutions to the two systems by using the inverse, i.e. by evaluating $A^{-1}B$ where $B$ represents the right hand side (i.e. $B = egin{bmatrix} -3 \ -3 end{bmatrix}$ for system (a) and $B = egin{bmatrix} -1 \ -2 end{bmatrix}$ for system (b)). Solution to system (a): $x = Box, y = Box$ Solution to system (b): $x = Box, y = Box$
Melissa Munoz
If A = [[- 7, 2], [- 2, 9]] then A^ -1 =[ ]. Given vec b =[ matrix -1\\ -2 matrix ], solve A vec x = vec b .; vec x =[ ].
Sam Stansfield
This limit h -> 0 (root(16 + h, 4) - 2)/h represents the derivative of some function f at some number a. State this f and a. a= f =
Find the value of the constant a that makes the following function continuous on (- ∞, ∞); f(x) = ((3x^3 - 12x^2 + 7x - 28)/(x - 4) x ^ 2 + 2x + a )) if x < 4; if x>= 4; a =
if A = [[1, 0, 0, 0], [3, 1, 0, 0], [4, 1, 1, 0], [4, 3, 1, 1]] then A^-1=
Given the matrix [[- 1, - 8, 1], [- 1, 1, - 1], [1, 3, 0]] (a) does the inverse of the matrix exist ? (b) if your answer is yes, enter the inverse of the matrix below.
if A = [[5, 10, - 34], [2, 5, - 16], [- 1, - 2, 7]], then A^-1=