Calculate the limit \lim_{x \to 3} \left( - \frac{\sqrt{x} + 6}{x^2 - x - 3} \right) Write your answer as a single number, giving either a whole number, a simplified fraction or a decimal number, rounded to two decimal places. If you think the answer is $+\infty$ or $-\infty$, write $+infinity$ or $-infinity$ respectively (no spaces, and don't include the quotation marks).