Use the information given below to find $\sin(\alpha-\beta)$.\newline$\tan\alpha = \frac{4}{3}$, with $\alpha$ in quadrant III\newline$\cos\beta = \frac{3}{5}$, with $\beta$ in quadrant I\newlineGive the exact answer, not a decimal approximation.\newline$\sin(\alpha-\beta) = $