A particular fruit's weights are normally distributed, with a mean of 211 grams and a standard deviation of 45 grams.
(a) If one fruit is randomly selected, what is the probability that its weight is between 185 and 216 grams?
Answer:
Round to 4 decimal places.
(b) What are the mean and standard deviation of the sample mean weight of 19 fruit?
Mean =
Standard deviation (standard error) $\frac{\sigma}{\sqrt{n}}$ =
Leave the square root in your answer.
(c) If you pick 19 fruit at random, what is the probability that their mean weight will be between 185 and 216 grams?
Answer:
Round to 4 decimal places.