4: An air-filled parallel plate capacitor of capacitance $C_o$ is connected to a battery $V_o$, and has a
charge $Q_o$. The battery is then removed and a porcelain slab of dielectric constant k=6 is
inserted and completely fills the space between the plates. The final charge Q, voltage V, and
capacitance C are equal:
\begin{enumerate}
\item $Q_o$, $\frac{V_o}{6}$, and $6C_o$
\item $Q_o$, $6V_o$, and $6C_o$
\item $Q_o$, $V_o$, and $\frac{C_o}{6}$
\item $6Q_o$, $\frac{V_o}{6}$, and $6C_o$
\item $Q_o$, $V_o$, and $6C_o$
\end{enumerate}
