Questions asked
Light of wavelength 525 nm is incident on a single slit. The intensity of the light at the center of a screen beyond the slit is 0.350 W/m2.What is the photon energy and momentum for this light? b. How many photons are detected per square millimeter per second? c. If very close to the first slit a second slit is now added. Does the number of photons detected per square millimeter per second at the very center of screen stay the same, double, or quadruple?
Three friends are sitting in a triangular park ABC . The sides \( \mathrm{AB}, \mathrm{BC} \) and CA are represented by lines \( y-x=0, x+y=0 \) and \( x-4=0 \) respectively. One friend draw partition through \( A \) to M. The partition AM divides the triangle into two equal parts. Based on the above information answer the following questions (i) Find the equation of the line AM . (ii) Find the area of the triangle \( A B C \)
Question 3 of 18 \( \square \) \( \square \) (Round to one decimal place as needed) Construct a \( 99 \% \) confidence interval for the popultion mean \( (\square \) \( \square \) (Round to one decimal place as needed) (Type an integer or a decimal Do not round) A. With \( \square \) B. \( \square \) C. It can be said that \( \square \) D. With \( \square \)
In an HIV infection over time, as CD4+ cells decline to a certain level, as determined by a flow cytometer technician, the patient's symptoms would progress and:
Find the Taylor series centered at $c = -1$. $f(x) = \frac{6}{3x - 2}$ Identify the correct expansion. $6 \sum_{n=0}^{\infty} \frac{3^n}{5^{n-1}}(x + 1)^n$ $-6 \sum_{n=0}^{\infty} \frac{3^n}{5^{n+1}}(x + 1)^n$
Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find the solution to the recurrence relation by using an iterative approach. Identify the missing steps, denoted by A and B, for the recurrence relation $a_n = (n+1)a_{n-1}$ with the initial condition $a_0 = 2$. (Check all that apply.) $a_n = (n+1)a_{n-1}$ $= (n+1)na_{n-2}$ $= (n+1)n(n-1)a_{n-3}$ $= (n+1)n(n-1)(n-2)a_{n-4}$ $= \dots$ continuing in the same manner $= (n+1)n(n-1)(n-2)(n-3)\dots (n-(n-2))a_{n-n}$ $= A$ $= B$ Check All That Apply A = $(n+1)n(n-1)(n-2)(n-3)\dots 2 \cdot a_0$ A = $(n+1)n(n-1)(n-2)(n-3)\dots a_0$ B = $2(n+1)!$ B = $(n-1)!$
(e) Let G be a group and let $a, b \in G$. Show that $(a \ast b)' = a' \ast b' \iff a \ast b = b \ast a$.
The forward converter has parameters $V_s = 90 \text{ V}$, $N_1/N_2 = N_1/N_3 = 1$, $L_m = 1 \text{ mH}$, $L_x = 80 \text{ }\mu H$, $R = 15 \text{ }\Omega$, $C = 33 \text{ }\mu F$, $D = 0.4$, and the switching frequency is 150 kHz.
as you read and reflected about each of the existential themes, which has the most meaning to you personally and why?
Zachary purchased a computer for $1,200 on a payment plan. Four months after he purchased the computer, his balance was $700. Five months after he purchased the computer, his balance was $575. What is an equation that models the balance y after x months?
