Learning Goal:
To find a position vector between two arbitrary points.
As shown, two cables connect three points. C is below A by a distance
C_z = 1.30 ft and connected to A by a cable 9.95 ft long. Cable AC forms an
angle \(\beta = 25.0^\circ\) with the positive y axis. B is 9.50 ft above C and the distances
\(B_x\) and \(B_y\) are 7.10 ft and 4.30 ft, respectively. (Figure 1)
Part A - Position vector from A to B
Using the dimensions in the figure, find the position vector from A to B in component form.
Express your answers, separated by commas, to three significant figures.
Part B - Unit direction vector for line AB
For the position vector found in Part A, find the unit direction vector acting in the same direction. Express your answer in component form.
Express your answers, separated by commas, to three significant figures.
Part C - Position vector from A to C
The length of cable AC is 9.95 ft, and the cable forms the angle \(\beta = 25.0^\circ\) with the y axis. Given this information and the dimensions provided in the figure, find the position vector from A to C.
Express the position vector in component form.
Express your answers, separated by commas, to three significant figures.