Use the given transformation to evaluate the integral, where R is the parallelogram bounded by the lines $y = -x + 1$,
y = -x + 4, y = 2x + 2, and y = 2x + 5.
$\iint_R (-5x + 3y) \, dx \, dy$; $u = x + y$, $v = -2x + y$
$\frac{61}{2}$
$\frac{49}{2}$
$\frac{61}{4}$
$\frac{49}{4}$