Example 6.4
Figure E6.4 shows the process and the known data. You are asked to calculate the compositions of every flow stream, and the fraction of the sugar in the cane (F) that is recovered in M.
M Sugar, 1000 lb/hr
lb
Mass Fraction
D = 16,755
$$\omega_S^D = 0.174$$
$$\omega_W^D = 0.026$$
E = 7819
F Cane
16% Sugar
25% Water
59% Pulp
Crystallizer
L Water
F = 24,574
$$\omega_W^E = 0.73$$
G = 1152
$$\omega_S^G = 0.014$$
K 40% Sugar
H = 6667
$$\omega_W^G = 0.036$$
E
H
Mill
Screen
Evaporator
J Water
J = 4167
$$\omega_W^H = 0.85$$
K = 2500
$$\omega_W^K = 0.60$$
L = 1500
D Bagasse
80% Pulp
Solids G Contain
95% Pulp
M = 1000