The distance between a point and a plane is given by the formula:
d = |Ax1 + By1 + Cz1 + D| / √(A^2 + B^2 + C^2)
In this case, the point P is (-7, -3, -4) and the plane is given by -8x + 2y + 3z = 2.
Therefore, the distance between the point P and the plane is:
d = |-8(-7) + 2(-3) + 3(-4) - 2| / √((-8)^2 + 2^2 + 3^2)