Numerade

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When two atomic orbitals combine in phase (constructively), what sort of MO is generated? a π style MO a σ style MO a bonding MO an antibonding MO

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Suppose a large corporation produces airplanes in a perfectly competitive industry. The data in the following table give information about the cost of producing a particular type of airplane (in thousands), where quantity is q, total cost is C, and marginal cost is MC. Airplanes sell for $80 thousand. q C MC 0 50 - 1 150 100 2 206 56 3 246 40 4 274 28 5 310 36 6 350 40 7 394 44 8 469 75 9 569 100 10 694 125 11 844 150 Suppose this firm has the capacity to produce up to 11 airplanes of this particular type. If the company manager's goal is to maximize revenue, how many airplanes will the firm produce?? airplanes. (Enter your response using an integer.) What will be the firm's profit? $? thousand. (Enter your response rounded to two decimal places.) Suppose instead that the manager's goal is to maximize profit. If so, then how many airplanes will the firm produce?? airplanes. (Enter your response using an integer.)

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UNKNOWN TITRATION Weight of unknown used Initial buret reading Final buret reading Volume NaOH used Weight KHP % KHP in unknown Calculations (show equations clearly): 26x1=26mol J 2.Lox 204.22 = 531S 1000 531 x 100 8421 = 63.06% Q-test of % KHP (90%): -2 NONE Confidence Limit of % KHP (95% confidence level): -5 Average % KHP ± 95% C.L. 66.014±2 Trial 1 .8421 0.00 26.00 53109 63.06% Trial 2 .8180 0.00 27.60 56403 68.95% Trial 3 .9715 0.00 31.50 64309 66.18% 27.6x.1=2.76 mol 131.5x.1= 3.15mo 27.6 x 204.22 = 5645 1000 564 x 100 8180 = 68.95% 3.15 x 204.22 100 1649x100 9715 = bla

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Text: Eating disorders are actually serious and often fatal illnesses that are associated with severe disturbances in people's eating behaviors and related thoughts and emotions. From the point of view of a nutritionist, discuss the possible nutrition intervention for eating disorders.

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A car can decelerate at -3.85 m/s^2 without skidding when coming to rest on a level road. What would its deceleration be if the road is inclined at 9.8° and the car moves uphill? Assume the same static friction coefficient.

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Problem 2. Consider the parametric curve $x = f(t) = t^2$, $y = g(t) = t^3 - t$, $ -\infty < t < \infty $. Prove that this curve intersects itself at precisely one point in the xy-plane. Find the parameters $t_1$ and $t_2$ such that $t_1 < t_2$, $f(t_1) = f(t_2)$ and $g(t_1) = g(t_2)$. At the intersection $(x, y) = (f(t_1), g(t_1)) = (f(t_2), g(t_2))$, there are two tangent lines to this parametric curve in the xy-plane. Find the slopes of these two tangent lines. Find the equations of the two tangent lines. Set up the definite integral that equals the length of the parametric curve from $t = t_1$ to $t = t_2$. Do not evaluate this integral. The parametric curve forms a closed loop for $t_1 \le t \le t_2$.

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Consider the circuit below where $R_D = 1.6 k\Omega$ and $\lambda = 0$, if the voltage gain is $A_v = 70 V/V$, then $R_s =$ $V_{DD} = 1.8 V$ Select one: a. None of these b. 300$\Omega$ c. 43.75$\Omega$ d. 22.86$\Omega$ Assume $I_s = 8 \times 10^{-16} A$, $\beta = 100$, $V_T = 26 mV$ and $V_A = \infty$. For the circuit shown below and for $I_1 = 1 mA$, the value of the transconductance is $V_{CC} = 2 V$ Select one: a. 76.92 mA/V b. 19.25 mA/V c. None of these d. 38.46 mA/V e. 315.30 mA/V

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\frac{5}{7} + \frac{6}{21} = \newline \frac{2}{15} + \frac{2}{6} = \newline 2\frac{1}{4} + 5\frac{3}{5} = \newline 20\frac{1}{2} + \frac{4}{5} =

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Activity 1.2: NOW IT'S YOUR TURN! A. Solve for the roots of the following quadratic equations using square root property. Show the solutions and encircle the final answer. 1. $x^2 = 225$ 2. $4x^2 - 196 = 0$ 3. $3(x + 2)^2 = 48$ 4. $9x^2 = 324$ 5. $(y + 3)^2 = 36$ B. Solve the following equations using quotient rule. Show your complete solution. 1. $12x^2 = 48x$ 2. $3x - 12x^2 = 0$ 3. $8r^2 - 15r = 25r$ 4. $120x - 12x^2 = 0$ 5. $210j^2 + 5j = -5j$

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3. Determine the correct formula for cos ratio of \angle A. A. $\cos A = \frac{adjacent}{hypotenuse}$ B. $\cos A = \frac{opposite}{hypotenuse}$ C. $\cos A = \frac{opposite}{adjacent}$ D. $\cos A = \frac{hypotenuse}{adjacent}$

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anna m.