Methanol, 175g, at a temperature of 20.0deg C absorbs 5.50kJ of heat. (c_(s))=(2.49(J)*g^(-1.deg C)C^(-1))
What is the final temperature of the methanol? Enter a numerical answer, omit the units. Use three sig fig.
c_(s)=(q)/((m)*Delta T)
Methanol,175 g,at a temperature of 20.0C absorbs 5.50 kJ of heat. (c,=2.49 J.g-1.C-1 )
What is the final temperature of the methanol?
Enter a numerical answer, omit the units. Use three sig fig
b
m.AT
