bi?n. Trong ?贸 ph?ii k? ??n c?ng C谩i M茅p Th? V脿i d脿i h?n 20 km . B谩c d??p l?, T?t. trong nh?ng ??a ?i?m thu h煤t kh谩ch t?i nghi d??ng, ??c bi?t v脿o c谩c d?p l?, T?t.
c. To?n: B脿i 1: Vi?t s? th铆ch h?p v脿o ch? ch?m:
\[
\begin{array}{l}
\text { d?c bi?t v脿o cacer } \\
\mathrm{m}: \\
834 \mathrm{dm}^{2}=\ldots \ldots .8 \ldots \mathrm{~m}^{2} \ldots 3.4 \ldots . \mathrm{dm}^{2} \\
\mathrm{dm}^{2}
\end{array}
\]
\( 3 \mathrm{~m}^{\frac{\mathrm{c}}{2}} 74 \mathrm{dm}^{2}=3.74 \ldots \mathrm{dm}^{2} \)
\( 8 \mathrm{~m}^{2} 50 \mathrm{dm}^{2}=8.50 \ldots \ldots \mathrm{dm}^{2} \)
\( 834 \mathrm{dm}^{2}= \)
\( 350 \mathrm{dm}^{2}= \)
\( 6 \mathrm{~m}^{2} 53 \mathrm{dm}^{2}=60.53 \ldots \mathrm{~cm}^{2} \)
\( 760 \mathrm{~cm}^{2}=\cdots \cdots \cdot \mathrm{dm}^{2} \) \( \qquad \) . 60 \( \qquad \) \( \mathrm{m}^{2} \)
\( 6 \mathrm{~m}^{2} 53 \mathrm{dm}^{2}=9 \mathrm{~m}^{2} 9 \mathrm{dm}^{2}=\ldots 9 . . . \mathrm{cm}^{2} \)
B脿i 2. Ng??i ta x芒y m?t h脿ng r脿o xung quanh m?nh ??t h矛nh ch? nh?t c贸 di?n t铆ch \( 220 \mathrm{~m}^{2} \), Chi??u r?ng cuua B脿i 3. M?t m?nh ??t h矛nh ch? nh?t c贸 chu vi 78 m , chi?u d脿i h?n chi锚ng C? tr?ng b?p c?i v脿 c脿 chua tr锚n m?nh B脿i 4. C么 H脿 c贸 m?t m?nh v??n h矛nh ch? nh?t d脿i 15 m v谩 v??n ?贸. Di?n t铆ch tr?ng c脿 chua l?n h?n di?n t铆ch tr么n chua.
B脿i 5. C么 H脿 tr?ng khoai lang tr锚n th?a ru?ng h矛nh ch? nh?t dai nhi锚u ki - \( 10 \hat{-} \) - gam khoai lang t? th?a ru?ng? H脿 thu ho?ch ???c 40 kg khoai lang. H?i c么 H脿 thu ???c bao nhi锚u ki - 10 - gam khoai lang tiut th卯a ru?ns t贸.
