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Kenneth

Kenneth

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A small 8.00 -kg rocket burns fuel that exerts a time-varying upward force on the rocket as the rocket moves upward from the launch pad. This force obeys the equation $F=A+B t^{2}$ . Measurements show that at $t=0,$ the force is $100.0 \mathrm{N},$ and at the end of the first 2.00 s, it is 150.0 $\mathrm{N}$ . (a) Find the constants $A$ and $B$ , including their SI units. (b) Find the net force on this rocket and its acceleration (i) the instant after the fuel ignites and (ii) 3.00 s after fuel ignition. (c) Suppose you were using this rocket in outer space, far from all gravity. What would its acceleration be 3.00 s after fuel ignition?

A small 8.00 -kg rocket burns fuel that exerts a time-varying upward force on the rocket as the rocket moves upward from the launch pad. This force obeys the equation $F=A+B t^{2}$ . Measurements show that at $t=0,$ the force is $100.0 \mathrm{N},$ and at the end of the first 2.00 s, it is 150.0 $\mathrm{N}$ . (a) Find the constants $A$ and $B$ , including their SI units. (b) Find the net force on this rocket and its acceleration (i) the instant after the fuel ignites and (ii) 3.00 s after fuel ignition. (c) Suppose you were using this rocket in outer space, far from all gravity. What would its acceleration be 3.00 s after fuel ignition?

University Physics with Modern Physics

A basketball player who is 2.00 $\mathrm{m}$ tall is standing on the floor 10.0 $\mathrm{m}$ from the basket, as in Figure $\mathrm{P} 4.54$ . If he shoots the ball at a $40.0^{\circ}$ angle with the horizontal, at what initial speed must he throw so that it goes through the hoop without striking the backboard? The basket height is $3.05 \mathrm{m} .$

A basketball player who is 2.00 $\mathrm{m}$ tall is standing on the floor 10.0 $\mathrm{m}$ from the basket, as in Figure $\mathrm{P} 4.54$ . If he shoots the ball at a $40.0^{\circ}$ angle with the horizontal, at what initial speed must he throw so that it goes through the hoop without striking the backboard? The basket height is $3.05 \mathrm{m} .$

Physics for Scientists and Engineers with Modern Physics

An airplane starting from airport A flies 300 $\mathrm{km}$ east, then 350 $\mathrm{km}$ at $30.0^{\circ}$ west of north, and then 150 $\mathrm{km}$ north to arrive finally at airport B. (a) The next day, another plane flies directly from A to B in a straight line. In what direction should the pilot travel in this direct flight? (b) How far will the pilot travel in this direct flight? Assume there is no wind during these flights.

An airplane starting from airport A flies 300 $\mathrm{km}$ east, then 350 $\mathrm{km}$ at $30.0^{\circ}$ west of north, and then 150 $\mathrm{km}$ north to arrive finally at airport B. (a) The next day, another plane flies directly from A to B in a straight line. In what direction should the pilot travel in this direct flight? (b) How far will the pilot travel in this direct flight? Assume there is no wind during these flights.

Physics for Scientists and Engineers with Modern Physics

(II) A projectile is fired with an initial speed of 36.6 m/s at an angle of 42.2$^\circ$ above the horizontal on a long flat firing range. Determine ($a$) the maximum height reached by the projectile, ($b$) the total time in the air, ($c$) the total horizontal distance covered (that is, the range), and ($d$) the speed of the projectile 1.50 s after firing.

(II) A projectile is fired with an initial speed of 36.6 m/s at an angle of 42.2$^\circ$ above the horizontal on a long flat firing range. Determine ($a$) the maximum height reached by the projectile, ($b$) the total time in the air, ($c$) the total horizontal distance covered (that is, the range), and ($d$) the speed of the projectile 1.50 s after firing.

Physics: Principles with Applications

KINEMATICS IN TWO DIMENSIONS; VECTORS

Projectile Motion

Questions asked

INSTANT ANSWER

A cannon is fired over level ground at an angle of 35 degrees to the horizontal. The initial velocity of the cannonball is 500 m/s, but because the cannon is fired at an angle, the vertical component of the velocity is 287 m/s and the horizontal component is 410 m/s. (a) How long is the cannonball in the air? (Use g = 10 m/s^2 and the fact that the total time of flight is twice the time required to reach the high point.) (b) How far does the cannonball travel horizontally? (c) Repeat the calculations, assuming that the cannon was fired at a 55 degree angle to the horizontal, resulting in a vertical component of velocity of 410 m/s and a horizontal component of velocity of 287 m/s. How does the distance traveled compare to the earlier result?

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INSTANT ANSWER

The velocity of a car increases with time. What is the average acceleration between 0-1 seconds?

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INSTANT ANSWER

Out of 1000 samples of 200 children each, in how many would you expect to find (i) less than 40% are boys, (ii) between 40% and 60% are girls.

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INSTANT ANSWER

2. Now suppose Cheerios has 3 grams of protein and 20 grams of carbohydrates per ounce. Rice Krispies has the same amounts as in Question 1: 2 grams of protein and 10 grams of carbohydrates per ounce. Also suppose Mr. Hernandez has now decided the twins can't eat more than 30 grams of carbohydrates each. However, they still need to eat at least 5 grams of protein each. What should the twins do now? a. Create equations to represent the situation. Label and describe your variables clearly. 2004-200 b. Find two equivalent equations of those you found in (a). c. State your solution (s) to the problem. Explain what they mean in the context of the situation.

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INSTANT ANSWER

Let an denote the number of subsets of a set containing n elements. Show that an+1 = 2an for all n ≥ 0. Hence find an.

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INSTANT ANSWER

Debye Theory II Use the Debye approximation to determine the heat capacity of a two-dimensional solid as a function of temperature. D State your assumptions. You will need to leave your answer in terms of an integral that one cannot do analytically. D At high T, show the heat capacity goes to a constant and find that constant. D At low T, show that C_v=KT^n. Find n. Find K in terms of a definite integral. Does g(w)=L^2((8piw)/((2pi)^2v^2))? If so can it be simplified anymore?

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ANSWERED

Drew Scalzo verified

Numerade educator

What would happen to the demand or quantity demanded in the market for oranges? There is an increase in the price of apples assuming apples and oranges are complements. _______________(demand/quantity demanded) for oranges______________ (decreases/increases) FILL THE BLANKS

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INSTANT ANSWER

lim (X,Y,Z)->(0,0,0) ((2X^2)+(3Y^2)+(4Z^2))/(X^2+Y^2+Z^2)

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INSTANT ANSWER

CHECKPOINT 22 QUESTION 1 lodate \( (V) \) lons react with acldified iodide lons as shown below: \[ 1 \mathrm{O}_{3}(\mathrm{aq})+5 \mathrm{H}(\mathrm{aq})+6 \mathrm{H}^{*}(\mathrm{aq}) \rightarrow 3 \mathrm{I}_{2}(\mathrm{~s})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \] The iodine released is then reacted with thiosulfate ions as given below: \[ \mathrm{b}_{2}(\mathrm{~s})+2 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-}(\mathrm{aq}) \rightarrow 2 \mathrm{l}(\mathrm{aq})+\mathrm{S}_{4} \mathrm{O}_{6}^{2-}(\mathrm{aq}) \] \( 60.0 \mathrm{~mL} \) of \( 0.200 \mathrm{M} \) iodate( \( \mathrm{V} \) ) ions reacted with excess acidified iodide ions. If all the lodine liberated reacted with \( x \mathrm{~mL} \) of \( 0.400 \mathrm{M} \) of thiosulfate ions, calculate the value of \( x \).

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INSTANT ANSWER

CHECKPOINT 20 QUESTION 1 \[ \mathrm{CaCO}_{3}+2 \mathrm{HCl} \rightarrow \mathrm{CaCl}+\mathrm{H}_{3} \mathrm{OS}+\mathrm{CO}_{2} \] A \( 2.00 \mathrm{~g} \) sample of limestone was dissolved in hydrochloric acid and all the calcium present in the sample was converted to \( \mathrm{Ca}^{2 *} \) (aq). Excess ammonium oxalate solution. \( \left(\mathrm{NH}_{4}\right)_{2} \mathrm{C}_{2} \mathrm{O}_{4}(\mathrm{aq}) \), was added to the solution to precipitate the calcium ions as calcium oxalate, \( \mathrm{CaC}_{2} \mathrm{O}_{4}(\mathrm{~s}) \). The precipitate was filtered, dried and weighed to a constant mass of \( 2.450 \mathrm{~g} \). Determine the percentage by mass of calcium in the llmestone sample. \[ \mathrm{Ca}^{2+}(\mathrm{aq})+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(\mathrm{aq}) \rightarrow \mathrm{CaC}_{2} \mathrm{O}_{4}(\mathrm{~s}) \] \[ \mathrm{Ca}_{\mathrm{C}} \mathrm{O}_{3}=\frac{2}{40.1+12+(16 \times 3)} \]

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