The Colebrook equation is given by
\[
\frac{1}{\sqrt{f}}=-0.86 \ln \left(\frac{\epsilon / D}{3.7}+\frac{2.51}{N_{R e} \sqrt{f}}\right)
\]
\( \checkmark \) Find the friction factor \( f \) for \( N_{R e}=6.5 \times 104 \) and \( \varepsilon / D=0.000 \)
