Consider the reaction of 2,2,4,4-tetramethylpentane with chlorine in light.
The first step is initiation in the presence of light.
$Cl-Cl \longrightarrow Cl \cdot + \cdot Cl$
Add curved arrows to show the mechanism of the propagation steps to form each monochlorination product shown.
a) Formation of the 1-chloro-2,2,4,4-tetramethylpentane.
$H-Cl$
$:Cl \cdot + H-CH_2 \longrightarrow \cdot CH_2 + :Cl-Cl \longrightarrow H_3C-CH_3$
$H_3C-CH_3$
$CH_3$
$CH_3$
$CH_3$
$CH_3$
$H_3C-CH_3$
$CH_3$
$CH_3$
$CH_3$
$CH_3$
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