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billy taylor

billy t.

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Question 5 0.5 pts The junction between two neurons where one neuron alters the electrical activity of the other is called a synapse. True False Question 6 1 pts Select the TWO myelin-producing glial cells. microglia oligodendrocytes astrocytes Schwann cells ependymal cells neurons Question 7 0.5 pt

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La viga mostrada soporta una fuerza distribuida w(x) = 23 kN/m, su longitud es x = 8 m. Determine el valor absoluto del momento flector en x = 2 m. Indique su respuesta en kNm utilizando 1 cifras decimal. w(x) X

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One year equals 365 days. The following program intends to read a floating-point value from input, convert the value from days to years, and output the quantity in years, but the code contains errors. Find and fix the errors.

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Suppose a piece of silver jewelry contains 7.94x10^{22} atoms of silver (Ag). Part A How many dozens of silver atoms are in the piece of jewelry? Express your answer numerically in dozens. 6.61x10^{21} dozen Correct Correct answer is shown. Your answer 6.52\times10^{21} = 6.52\times10^{21} dozen was either rounded differently or used a different number of significant figures than required for this part. Part B How many moles of silver atoms are in the piece of jewelry? Express your answer numerically in moles. Part C Complete previous part(s)

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what is correct needle, syringe, and injection site for a patient that is 49 years old, weighs 159 kg, and medication is ceftriaxone sodium 1 gram per 2.1 ml (IM)

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Which is the last amino acid if glycine is not an option

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If you are vomiting and have diarrhea, what is likely to be your doctor's main concern? That you do not lose too much weight That you do not become dehydrated That you do not develop a high fever

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True

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Evaluate the definite integral by using Fundamental Theorem of Calculus: $\int_0^4 \sqrt{1 + x^2} dx$

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The mass of a steel wrecking ball is 1.50 x 10^3 kg. What power is used to raise it to a height of 45.0 m if the work is done in 15.0 seconds? I calculate: Work done = potential energy = mgh Power = mgh/t Gravity = 9.8 m/s^2 M = 1.5 x 10^3 kg = (1500 kg) Height – 45 meters Time – 15 seconds P = (1500 kg)(9.8 m/s^2)(45 meters) / (15 seconds) W P = 44100 W or 4.4 x 10^4 Rearranging the formula, we get: F=dmgh The force applied to the wrecking ball is equal to the weight of the ball, which is given by: F=mg Substituting the given values, we get: F = (1500 kg)(9.81 m/s^2) = 1.47 x 10^4 N Therefore, the power used to raise the steel wrecking ball to a height of 45.0 m in 15.0 seconds is: P = W/t = Fdh/dt = (1.47 x 10^4 N)(45.0 m) / 15.0 s = 4.41 x 10^4 W

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