Numerade

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Explain why the function is differentiable at the given point. $f(x, y) = y \tan(x)$, $(\frac{\pi}{4}, 4)$. The partial derivatives are $f_x(x, y) = $ and $f_y(x, y) = $ so $f_x(\frac{\pi}{4}, 4) = $ and $f_y(\frac{\pi}{4}, 4) = $ Find the linearization $L(x, y)$ of the function at $(\frac{\pi}{4}, 4)$. $L(x, y) = $

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Regarding behavioral traits. Group of answer choices Genes that effect our behavioral traits can either be expressed or not. All answers are correct. Personality is pretty much hard wired in us. Temperement is pretty much establised at birth. Groups of genes which interact with one another effect our temperment.

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Mean Length of babies is 48 cm, Standard deviation is 5.2 cm. What is probability of baby measuring at least 70 cm

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2: a. the square loop (with side length 2m) is perpendicular to a 3T magnetic field. Over a period of 10s, the field increases to 5T. Describe and explain the direction of the current induced in the loop.

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Which of the following is responsible for dissolving a blood clot? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a fibrin b plasmin c tissue factor d thrombin

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Problem 6: Use the Von Neumann analysis to determine stability properties of the scheme for the 2nd order central discretization in space with implicit 1st order difference in time of the 1D heat equation. $\frac{\partial u}{\partial t} = a^2 \frac{\partial^2 u}{\partial x^2}$

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One of the genes responsible for mouse fur color is gene A. The phenotypes resulting from the A gene are as follows: • AYAY is embryonic lethal due to problems during development. • AY a mice have yellow fur. • aa mice have black fur. A second independently assorting gene C determines if the color is produced. • The CC and Cc genotypes allow color according to the A allele. • The cc genotype results in albino mice regardless of the A allele. A cross between AYaCc \times AYaCc results in 48 progeny mice that are albino, yellow, or black.

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The following section is taken from Tamarisk's balance sheet at December 31, 2021. Current liabilities Interest payable $46,000 Long-term liabilities Bonds payable (8%, due January 1, 2025) 575,000 Interest is payable annually on January 1. The bonds are callable on any annual interest date. (a) Journalize the payment of the bond interest on January 1, 2022. (b) Assume that on January 1, 2022, after paying interest, Tamarisk calls bonds having a face value of $170,000. The call price is 106. Record the redemption of the bonds. (c) Prepare the adjusting entry on December 31, 2022, to accrue the interest on the remaining bonds. (Credit account titles are automatically indented when amount is entered. Do not indent manually. If no entry is required, select \"No Entry\" for the account titles and enter 0 for the amounts.) No. Date Account Titles and Explanation Debit Credit (a) Jan. 1 (b) Jan. 1 (c) Dec. 31

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Simplify.\\ \frac{54y}{5x - 9y} + \frac{30x}{9y - 5x} =

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3.) For a point on the unit circle in quadrant 2, cot (theta) = -20. Calculate the (x,y) coordinates for this point. 4.) Solve for theta: 2cos^3 + cos^2(theta) - 2cos(theta) - 1 = 0 3.1 point: For a point on the unit circle in Quadrant II, cot = -20. Calculate the (x,y) coordinates for this point. Must show all the steps using the methods shown in class for the unit circle. 4.4 points: Solve for 92cos + cos = 2cos - 1 = 0, 0. First set x = cos then use the fact that one of the zeros of 23 + 2 - 2x - 1 = 0 is = 1.

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bonnie w.