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carla cross

carla c.

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Question 19 (0.1111 points) Using human karyotyping one can find out the following: Number of chromosomes are present in a cell. If any chromosome is missing. If any chromosome is extra. If a part of any chromosome is brocken. All of the above.

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Multiple Choice 10 points In a certain region of space, the electric potential is 3 V everywhere along the x axis. From this information, you can conclude that the electric field in this region is in the positive x direction in the negative x direction in the vertical direction zero

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A particle is moving in x-y plane, its position vector is given by \(\vec{r} = [(6 + 3t)\hat{i} + (5 + 2t - 2t^2)\hat{j}]\) m, where t is measured in seconds. a) Find its position vector and velocity vector at \(t = 0\) s (in unit vector notation). b) Find the acceleration of the particle (in unit vector notation). c) How long (in s) will take the particle to reach the maximum y-coordinate?

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How is the direction of current flow defined in a conductor? It is in the direction of the force on a charged particle

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Use of PI control along with P control facilitates Elimination of offset Reduction of offset Reduction of stability time None of these

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Calculate the Voltages and currents in the circuit, in polar, rectangluar and complex form Source frequency is 60Hz 100V0Y R 30u 100 0 Circuit 4

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Question 5 (1 point) Unequal Lives. Your company is considering two machines to stamp metal in its factory. Machine A costs $500,000, it has a life of four years, and it will generate after-tax cash flows of $190,000 each year. Machine B costs $300,000, has a life of three years, and will generate after-tax cash flows of $150,000 each year. The company's WACC is 13% per year. Calculate Equivalent Annual Annuities (EAA's). Which machine should your company purchase? 1) A=$23,903; B=$22,943. Choose A 2) A=$21,903; B=$22,943. Impossible to determine. 3) A=$21,903; B=$22,943. Choose B 4) A=$20,000; B=$22,000. Choose B 5) A=$23,903; B=$22,943. Impossible to determine.

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In the government budget deficit will the real interest rate, as can be explained using the market for loanable funds.

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Consider the following control system: Controller Plant $r(t)$+ \(e(t)\) - $x(t)$ $C(s)$ $G(s)$ $y(t)$ where the design objective is to achieve (i) stability and (ii) no steady state error (i.e. $\lim_{t \to \infty} e(t) = 0$) when $r(t) = u(t)$. (a) Prove that $\frac{Y(s)}{R(s)} = \frac{C(s)G(s)}{1 + C(s)G(s)}$ $\frac{E(s)}{R(s)} = \frac{1}{1 + C(s)G(s)}$ (b) Show that this control problem can be solved if $C(s)$ satisfies i. all roots of $1 + C(s)G(s)$ have negative real parts; ii. $\lim_{s \to 0} |C(s)G(s)| = \infty$. (c) Suppose that the transfer function of the plant is given by $G(s) = \frac{1}{s(s - 1)}$. Prove that the controller given by the formula $x(t) = K_p e(t) + K_d \frac{de(t)}{dt}$ can be used to satisfy the conditions in part (b). Can you set $K_p$ and $K_d$ to any values?

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A plant has a capacity of 4,100 hydraulic pumps per month. The fixed cost of this capacity is $504,000 per month. The variable cost is $166 per pump, and the sales price is $328 per pump. 1-The break-even point in number of pumps per month is unit. 2-The revenue at the break-even point is $ 3-The profit at the plant capacity is $ 4-The percentage reduction that will occur in the break-even point if the fixed cost is reduced by 18% and unit variable cost by 6% at the same time is %.

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