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The molar mass of silver phosphide, Ag3P, is 354.58 g/mol. What is the mass (in grams) of 2.88 x 1023 formula units of silver phosphide?

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2 of the answers are NOT correct. Consider the function $F(s) = \frac{2s + 6}{s^3 - 3s^2 + 3s - 1}$. a. Find the partial fraction decomposition of $F(s)$: $\frac{2s + 6}{s^3 - 3s^2 + 3s - 1} = \frac{1}{(s - 1)^2} + \frac{4}{(s - 1)^3}$ b. Find the inverse Laplace transform of $F(s)$. $f(t) = \mathcal{L}^{-1}\{F(s)\} = 2t(1 + 2t)e^t$

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2. Consider the unbalanced reaction: _ _ NHs (g) + __ 02 (g) ->. NO (g) + _ _H20 (g) a. How many moles of nitrogen monoxide are formed if 4.50 moles of water are formed

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Insulin is secreted binding of insulin to the a subunit of the insulin receptor phosphorylation of IRS proteins activation of insulin receptor tyrosine kinase phosphorylation of phosphoinositide 3-kinase (PI-3K) conversion of PIP$_2$ to PIP$_3$ activation of PIP$_3$-dependent protein kinase B (PDK1) activation of Akt GLUT4 receptors transported to cell membrane Glucose enters cell Answer Bank

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5. The structure of saxagliptin, which is a covalent inhibitor and is used to treat type 2 diabetis is shown below. The drug functions through inhibition of serine protease enzymes involved in hormone degradation. Propose a mechanism (arrowpushing) on the molecule below. As a guide, first look at the molecule below and identify what you think is the best electrophile!

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Which of the following is NOT an aging-dependent problem of the lymphatic system? Increased susceptibility to infection Reduced number of helper T cells Cancer incidence increases Inflammation increases in appendix Lymphocytes become less responsive

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he chromosome complement of the mature pea plant is called , whereas the complement of the gametophytes and gametes is called . In the sporophyte (diploid, 14 chromosomes) pea plant, after mitosis, each of the two daughter cells have chromosomes. After meiosis (both divisions) in the sporophyte plant, each of the four daughter cells have chromosomes. During the first meiosis division (M1), the pair and crossing-over (genetic exchange) occurs between their non-sister chromatids. The spindle then moves them to opposite sides of the cell, which results in a set of chromosomes in each daughter cell. Because it reduces the chromosome sets from to haploid, the M1 division is called the "reductional" division of meiosis. The daughters of M1 each receive only one of each chromosome - also only one gene - for each pair of chromosomes - or genes - in the parent cell, not both. This demonstrates Mendel's law of . During M1, when one homologue segregates into a daughter cell, it does not influence which of the two homologues for the other homologous chromosome pairs also segregates into that daughter cell. That means, that for different traits, inheriting a particular allele for one trait (like the yellow allele for pea color), does not influence whether a particular allele for a different trait (like round R or wrinkled r) is also inherited. This demonstrates Mendel's law of . Since the chromosomes are replicated during S phase for both mitosis and meiosis, the single homologues in the daughter cells of the first meiosis division (M1) still have sister chromatids attached by a centromere. In order to make the gametes, these daughters undergo the second meiosis division (M2), so each gamete has only one copy of a haploid number of chromosomes. This M2 division is the same as

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why are point mutations generally less serious than a chromosomal alteration?

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CURRENT OBJECTIVE Calculate continuous growth and decay Question In 2005 the population of a district was 35,700 with a continuous annual growth rate of approximately 4%, what will the population be in 2030 according to the exponential growth function? Round the answer to the nearest whole number, do not include the unit in your answer. Provide your answer below:

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Part C The formal charge on Br in the Lewis structure is +2 and the formal charge on the O atoms is -1.. What is the average Br-O bond order?

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