7.134 For the emitter-follower circuit shown in Fig. P7.134,
the BJT used is specified to have $\beta$ values in the range
of 50 to 200 (a distressing situation for the circuit designer).
$i_{sig}$
100 $k\Omega$
10 $k\Omega$
Figure P7.134
$R_{in}$
+3 V
1 $k\Omega$ 1 $k\Omega$
please choice the correct answer:
When $\beta$=50: $I_E$ = 0.777mA, $V_E$=0.777V, $V_B$=1.477V, $R_{in}$=22.33$k\Omega$, $A_v$=0.6126V/V. When $\beta$=200: $I_E$ = 1.135mA, $V_E$=1.135V, $V_B$=2.135V, $R_{in}$=50.92k$\Omega$, $A_v$=0.481V/V.
Correct answer is not provided.
When $\beta$=50: $I_E$ = 0.777mA, $V_E$=0.777V, $V_B$=1.477V, $R_{in}$=22.33$k\Omega$, $A_v$=0.6126V/V. When $\beta$=200: $I_E$ = 1.535mA, $V_E$=1.535V, $V_B$=2.235V, $R_{in}$=50.92k$\Omega$, $A_v$=0.81V/V.
When $\beta$=50: $I_E$ = 0.577mA, $V_E$=0.577V, $V_B$=1.277V, $R_{in}$=22.33$k\Omega$, $A_v$=0.82126V/V. When $\beta$=200: $I_E$ = 1.535mA, $V_E$=1.535V, $V_B$=2.235V, $R_{in}$=50.92k$\Omega$, $A_v$=0.81V/V.
