Determine if the improper integral is convergent or divergent, and find its value if it is convergent.\n$\int_2^\infty \frac{1}{9x^2} dx$\nSelect the correct choice below and, if necessary, fill in the answer box to complete your choice.\nA. The improper integral is convergent and $\int_2^\infty \frac{1}{9x^2} dx = $\n(Type an integer or a fraction. Simplify your answer.)\nB. The improper integral diverges.