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christopher hanson

christopher h.

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2) Acrylic acid will be extracted from its aqueous mixture, containing 5 mole percent acrylic acid, by using pure di-isopropyl ether (DIISO-01) through stage wise contact in a counter-current extraction system at 25 °C. a) Draw a block diagram of the system containing N stages, and please mark and label all the streams in it. b) If the acrylic acid content in the raffinate product is 10 mole percent of that in the raffinate feed, what will be the minimum solvent flow rate required for the raffinate feed flow rate of 20 kgmol/h? c) When the solvent flowrate used is 1.5 times the minimum solvent flowrate, what will be the number of stages needed? d) Show the flow rates and compositions of the raffinate and extract phases around the second stage? e) Calculate the recovery in the system. Solubility and distribution diagrams of acrylic acid, water and di-isopropyl ether ternary system at 25 °C is given in Figure Q 2. pMmin = 0.0475 0.0497 Smin = 1.0455 Mmin = 21.0455 Stages R xA xB E yA yB 1 18 0.0335 0.0044 4 0.2275 0.3799 2 18 0.0235 0.0037 3 0.1838 0.5398 3 18 0.0168 0.0032 2 0.1441 0.6649 4 18 0.0118 0.0029 2 0.1045 0.7701 5 18 0.0086 0.0028 2 0.0663 0.8533 6 18 0.0048 0.0025 2 0.037 0.905 Solubility Curves of AcrylicAcid in Water and in DIISO-01 at 25 °C $x_{DIISO-01}$ or $y_{DIISO-01}$ $x_{AcrylicAcid}$ or $y_{AcrylicAcid}$ Distribution Curve of AcrylicAcid between Water and DIISO-01 at 25 °C $y_{AcrylicAcid}$ mol fraction of AcrylicAcid in DIISO-01 $x_{AcrylicAcid}$ mol fraction of AcrylicAcid in Water Figure Q 2 Solubility and distribution diagrams of acrylic acid, water, and di-isopropyl ether ternary system at 25 °C.

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Let $E$ be the solid in $\mathbb{R}^3$ which lies between the $xy$-plane and between the following surfaces 1. the planes given by $y = 0$-plane and $y = 4$ 2. the planes given by $x = 0$-plane and $x = 5$ 3. the graph of the function $f:\mathbb{R}^2 \to \mathbb{R}$, $f(x,y) = 9 - x \cdot y$ Find the volume $V$ of $E$. Hint: Draw a sketch of the situation and, in particular, of the domain $D$ over which you want to integrate.

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Diffusion coefficient $$ln D = ln D_0 - \frac{Q_d}{R}(\frac{1}{T})$$ not dependent on T stays constant with change in T increases with increasing T decreases with increasing T

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22.4 The Electric Field Due to a Line of Charge A total charge of $6.3 \times 10^{-8}$ C is distributed uniformly throughout a 2.7-cm radius sphere. The volume charge density is $7.6 \times 10^{-4} \, C/m^3$ $6.9 \times 10^{-6} \, C/m^3$ $3.7 \times 10^{-7} \, C/m^3$ $2.5 \times 10^{-4} \, C/m^3$ $6.9 \times 10^{-6} \, C/m^2$

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If a 1050-kg car was moving at 25 m/s, what would be its kinetic energy expressed in the unusual (for kinetic energy) units of calories? (1 cal = 4.186 J) Group of answer choices 7.8E+4 3.1E+5 6.3E+3 6.6E+5 3.3E+5

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You may need to use the appropriate appendix table or technology to answer this question. Given are five observations collected in a regression study on two variables. \begin{tabular}{|c|c|c|c|c|c|} \hline $x_i$ & 2 & 6 & 9 & 13 & 20 \\ \hline $y_i$ & 7 & 19 & 8 & 27 & 23 \\ \hline \end{tabular} Develop the 95\% confidence and prediction intervals when $x = 8$. (Round your answers to two decimal places.) confidence interval $oxed{x}$ to $oxed{x}$ prediction interval $oxed{x}$ to $oxed{x}$ Explain why these two intervals are different. The two intervals are different because you use a different critical value when developing a confidence interval than when developing a prediction interval. The two intervals are different because confidence intervals are used to predict values of $y$ for new observations corresponding to given values of $x$, and prediction intervals give an estimate of the mean value of $y$ for a given value of $x$. The two intervals are different because there is more variability associated with predicting an individual value than there is with estimating a mean value. The two intervals are different because there is less variability associated with predicting an individual value than there is with estimating a mean value.

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What mass of nitric oxide is produced by the reaction of 9.6 of ammonia?

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Goals of occupational therapy should: Be vague and flexible Be determined exclusively by the professional Reflect caregiver priorities and the needs of the child in everyday environments Be separate from other detailed information about functioning

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Explain the purpose of and matters that must be included in an audit engagement letter

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29.A nurse is reinforcing teaching with an adult client who has a low literacy level about the subcutaneous administration of medication. Which of the following strategies should the nurse use to promote the client's understanding?A. Use technical words and short sentences.B. Ask the client to demonstrate the skill.C. Provide the client with written, large-print materials.D. Plan for a long teaching session

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