To solve this problem, we can use the stoichiometry of the balanced chemical equation to determine the amount of silver sulfate formed. First, we need to convert the moles of AgNO3 and Na2SO4 to moles of Ag2SO4 using the coefficients in the balanced equation. Then, we can use the molar mass of Ag2SO4 to convert moles to grams.
Step 1: Convert moles of AgNO3 to moles of Ag2SO4
0.26 mol AgNO3 × (1 mol Ag2SO4 / 2 mol AgNO3) = 0.13 mol Ag2SO4
Step 2: Convert moles of Na2SO4 to moles of Ag2SO4
0.18 mol Na2SO4 × (1 mol Ag2SO4 / 1 mol Na2SO4) = 0.18 mol Ag2SO4
Step 3: Add the moles of Ag2SO4 from both reactants
0.13 mol + 0.18 mol = 0.31 mol Ag2SO4
Step 4: Convert moles of Ag2SO4 to grams
0.31 mol Ag2SO4 × (311.8 g Ag2SO4 / 1 mol Ag2SO4) = 96.758 g Ag2SO4
Therefore, when a solution containing 0.26 mol AgNO3 is mixed with a solution containing 0.18 mol Na2SO4, 96.758 grams of silver sulfate are expected to form.