Listed below are the numbers of words spoken in a day by each member of eight different
randomly selected couples.
Male: 15615, 26374, 1418, 8032, 18306, 15606, 13660, 24960
Female: 24394, 13482, 17773, 17118, 12776, 16989,16098, 18985
Use a 0.01 significance level to test the claim that among couples, males speak fewer words
in a day than females. In this example, $\mu_d$ is the mean value of the differences $d$ for the
population of all pairs of data, where each individual difference $d$ is defined as the words
spoken by the male minus words spoken by the female. What are the null and alternative
hypotheses for the hypothesis test?
$H_0: \mu_d$ [Select] 0 word(s)
$H_1: \mu_d$ [Select] 0 word(s)
Identify the test statistic. (Round to two decimal places as needed.)
t= [Select]
Identify the P-value. (Round to three decimal places as needed.)
P-value = [Select]
What is the conclusion based on the hypothesis test? Since the P-value is
[Select] the significance level, [Select] the
null hypothesis. There [Select] sufficient evidence to support the
claim that males speak fewer words in a day than females.
Construct the confidence interval that could be used for the hypothesis test described in part
(a). What feature of the confidence interval leads to the same conclusion reached in part (a)?
The confidence interval is [Select] word(s) $< \mu_d <$
[Select] word(s).
What feature of the confidence interval leads to the same conclusion reached in part (a)?
Since the confidence interval contains [Select] ,
[Select] the null hypothesis.
