Given the differential equation $v' + 9v = (t \times \cos(3 \times t^2))u(t)$
Using Euler's method to compute $v(t + h)$ from information of the function at time $t$, i.e., you know $v(t)$ and initial condition.
$v(t + h) = v(t) + h$
$v(t) + h$
For $h = 0.1$, compute the solution for $t = 0, 0.1, 0.2, 0.3$, when the initial condition is $v(0) = 3$.
$v(0) = $
$v(0.1) = $
$v(0.2) = $
$v(0.3) = $
