Consider a system of three particles:
One particle has mass m1= 2 kg, position rβ1= <β5,β1,0> m, and velocity vβ1= <3,β2,β5> m/s.
The second particle has mass m2= 9 kg, position rβ2= <4,2,0> m, and velocity vβ2= <8,β10,0> m/s.
The third particle has mass m3= 9 kg, position rβ3= <4,4,0> m, and velocity vβ3= <6,β8,0> m/s.
Find the total momentum of the system consisting of all three particles.
kg m / s
One way to think of systems made of many parts is to separate the motion into two parts. One part is the center of mass motion. This treats the whole system as single object, a point that has the entire mass of the system and is located at the system's center of mass.
Find the velocity of the center of mass of the system.
m/s
The total kinetic energy of the system can be found by adding up all of the individual kinetic energies. This number represents the total kinetic energy the system shares among its different parts.
What is the total kinetic energy of this system?