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crystal mcdonald

crystal m.

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Hartford Mining has 80 million shares that are currently trading for $2 per share and $130 million worth of debt. The debt is risk free and has an interest rate of 7% (debt cost of capital). The expected return of Hartford stock is 12% (equity cost of capital). Suppose Hartford decides to borrow an additional $30 million and uses this amount to repurchase shares of stock and reduce equity by $30 million. The interest rate on debt remains unchanged. Assume perfect capital markets (no taxes) and the risk (unlevered beta) of Hartford's assets is unchanged. Round all answers to two decimals. 1. What is Hartford's new debt-to-equity ratio after additional borrowing? 1.625 (2 points) 2. What is Hartford's stock price after additional borrowing? $ (2 points) 3. What is Hartford's unlevered cost of equity (r<sub>u</sub>) (in %)? % (4 points) 4. What is Hartford's equity cost of capital (r<sub>e</sub>) after additional borrowing (in %)? % (4 points)

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Entered Answer Preview Result (3/2-x/4)^2 ($\frac{3}{2} - \frac{x}{4}$)$^2$ m incorrect x^2/(4*pi) $\frac{x^2}{4\pi}$ m incorrect 2.63940507893066 m $\frac{6\pi}{4 + \pi}$ m incorrect 3.36059492106934 m $\frac{24}{4 + \pi}$ m incorrect Message Your answer isn't a number with units (it looks like a formula that returns a number) Your answer isn't a number with units (it looks like a formula that returns a number) At least one of the answers above is NOT correct. A wire 6 meters long is cut into two pieces. One piece is bent into a square for a frame for a stained glass ornament, while the other piece is bent into a circle for a TV antenna. To reduce storage space, where should the wire be cut to minimize the total area of both figures? Give the length of wire used for each: For the square: ($\frac{3}{2} - \frac{x}{4}$)$^2$ m For the circle: $\frac{x^2}{4\pi}$ m (for both, include units) Where should the wire be cut to maximize the total area? Again, give the length of wire used for each: For the square: $\frac{6\pi}{4 + \pi}$ m For the circle: $\frac{24}{4 + \pi}$ m (for both, include units)

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Part 1 Find the following derivatives. z_subscript_s and z_subscript_t, where z = 2x + 5y, x = 7s*t, and y = 3s + 9t

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(a)Express the number shown in the box as a number in base THREE ooooooooooooooooooooooooooooooooooooooooooo (b)Express the number shown in the box as a number in base TWO ooooooooooooooooooooooooooooooooooooooooooo

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Traverse all the nodes of the given graphs using BFS (Breadth First Search) Algorithms.

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10) (10) Given $A^{-1} = \begin{bmatrix} 3 & -4 \ -1 & 2 \end{bmatrix}$ and a polynomial $p(x) = x^3 - 2x + 4$. Find $p(A)$

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S1 S2 S3 S4 S5 Ave SD 50 51 50 52 53 51.2 1.3038405 33 32 30 31 32 31.6 1.140175 37 38 39 40 40 38.8 1.303840 44 45 43 45 42 43.8 1.30384( 50 49 48 52 52 50.2 1.788854 55 56 54 55 57 55.4 1.140175

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2. The following questions deal with manipulating complex expressions. (a) \( (3e^{j\theta_1}) \cdot (2e^{j\theta_2}) = Ae^{jB} \). Find A and B. (b) \( e^{(x+jy)t} = Ae^{jB} \). Find A and B, which may be functions of time. (c) \( 3e^{\frac{\pi}{2}j}e^{(-2+3j)t} = Ae^{jB} \). Find A and B. (d) Write \( e^{j0}e^{(-2+3j)t} + e^{-j0}e^{(-2-3j)t} \) as a real-valued function of time. [Hint: use Euler's formula: \( e^{jx} + e^{-jx} = 2cos(x) \).

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Exercises 11-15: Rewrite the given scalar differential equation as a first order system, and find all equilibrium points of the resulting system. 11. $y'' + y + y^3 = 0$ 13. $y'' + \frac{2y'}{1 + y^4} + y^2 = 1$ 15. $y''' - (y')^2 + \frac{4 - y^2}{2 + (y')^2} = 0$ 12. $y'' + e^y y' + sin^2 \pi y = 1$ 14. $y''' - y'' + 2 sin y = 1$

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Our work. Box your answers. 1. A sequential switching second-order circuit can be modeled when the gate function shown in Figure 1b is applied to the parallel RLC circuit shown in Figure 1a. Let v0 = 10V and i0 = 0A. R = 400Ω L = 1.25H C = 1.25F t [ms] 0 50 Figure 1 (a) Figure 1a (b) Figure 1b a) Find v(t) and i(t) for 0 < t < 50ms. (7 points) b) Find v(50ms), i(50ms), and v'(50ms). (3 points) c) Find i(t) and v(t) for t > 50ms. (5 points) Parameters to generate v(t): Table 1: Generating v(t) T1 T2 T3 T4 0 0.001ms 50ms 50.001ms V1 V2 V3 V4 0 32V 32V 0 Also, set the initial condition of the capacitor to 10V and set the initial condition of the inductor to 0A. Your simulation run time should be 100ms long with a maximum step size of 10ps.

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