The question is to show that the expressions of Ey and Ez below are indeed solutions of the wave equation above. As seen in the photo, the HW (homework) in red font is the question I need to solve.
Polarized Waves Ex, E=0, H=0, Hxt Linear Polarization Direction CE, 3.0
Polarized waves: E=0, H=0
FE
F
ax CH, CH ar 3.0
wavelength [v: circular frequency; = 2v VI
-p- E, cxp1(cE, exp[erx]
Vacuum: c, C,
1==
Simple refractive index=1
Dielectric: c,
=Ecxp
xf-
12E
Polarized Waves Ext), Ext)Eiptical Polarization
HW: Show that the expressions of E, and E, below are indeed solutions of the wave equations above.
E=Ecos-kx=Ecos=cost=
plon
HET
E=Ecos-kx+=Ecost+=Ecostcos-sinsin
cs-1sin=+-o=snAnclips
Polarized Waves E,xt), E,x,tcon.