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daniel shaw

daniel s.

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Female sea turtle hatchlings tend to do better if they hatch early in the hatching season, so they have more time to grow after hatching. But male hatchling success is not dependent on hatching time. Based on what you know about sea turtle nests, what can you tell me about the weather early in the sea turtle hatching season?

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One of the weaknesses of NAFTA, according to the lecturer, is the political instability that it caused in Mexico. true or false?

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Which of the following does not impact creditworthiness? Question 22 options: 1) Job security 2) Income 3) Gender 4) Wealth 5) None of the above

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Question 49 1 Point The Canadian Model of Occupational Performance and Engagement has the following construct at the core or center of the model: A Spirituality B Person C Environment D Occupation

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Question 11 2 pts In many circumstances, participants correctly recognize that a stimulus is familiar, but they are mistaken in their beliefs about where and when they encountered the stimulus. This error is referred to as source confusion. origin error. amnesia. false identification.

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Question 8 Factor completely, if possible. x^(2)-x-72 (x+9)(x-8) Prime (x+8)(x-9) D) (x+1)(x-72) Question 8 Factor completely,if possible x2--72 x+9x-8 B Prime x+8x-9 Th +1-72

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I. Conductors and Electric Potential A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d, as shown in the figure. The shells have total net charges of +2q (on the smaller shell) and +4q (on the larger shell). Two methods (both involving integration) are available to calculate the electric potential for a configuration of charges. If we already know the electric field everywhere (or can find it easily), it is often better to use Delta V=-int vec(E)*dvec(s) instead of V=k_(e)int (dq)/(r). a) Please take a moment to discuss with your teammates how you used Gauss's Law last week to find the electric field in each of the regions. In which region(s) is the electric field zero? It may help to fill in the table at right, specifying the charge on each surface. b) Given the graph below of the electric field E as a function of r, please draw a corresponding graph of the electric potential V as a function of r. (Hint: consider what happens to the change in electric potential in regions where E>0 vs. regions where E=0.) c) Starting at infinity, where electric potential is set to be zero, please calculate the electric potential, as a function of r, in the region r>d. d) How can we use this to find the electric potential at r=c ? Please explain. e) Since it is within a conductor, we know that the electric field is zero in the region r=dr=cr, starting from infinity where electric potential is zero. Does the electric field change in the region(s) you are integrating over? If so, how does this affect the integration?b, starting from infinity where electric potential is zero. Does the electric field change in the region(s) you are integrating over? If so, how does this affect the integration? gc. i I.Conductors and Electric Potential A small conducting spherical shell with inner radius a and outer radius b is concentric with a larger conducting spherical shell with inner radius c and outer radius d, as shown in the figure. c) Starting at infinity, where electric potential is set to be zero, please calculate the electric potential, as a function of r, in the region r > d. The shells have total net charges of +2q (on the smaller shell) and +4q (on the larger shell). d) How can we use this to find the electric potential at r = c? Please explain. Two methods (both involving integration) are available to calculate the electric potential for a configuration of charges. If we already know the electric field everywhere (or can find it easily), it is often better to use V=E-d5 instead ofV=, J dq a)Please take a moment to discuss with your teammates how you used Gauss's Law last Smaller shell (r=) 0 week to find the electric field in each of the regions. In which region(s) is the electric Smaller shell (r=b) field zero? It may help to fill in the table at right, specifying the charge on each surface Larger shell (r=c) e) Since it is within a conductor, we know that the electric ficld is zero in the region c < < d. i) What does this mean for the electric potential in this region? Larger shell (r=d) +6q ii) What would be the work done moving a charge from r = d to = c? b) Given the graph below of the electric field E as a function of r, please draw a corresponding graph of the electric potential V as a function of r. (Hint: consider what happens to the change in clectric potential in regions where E > 0 vs. regions where E = 0.) 1 Write down (but do not solve) the integral equation for calculating the electric potential in the region b < < c, starting from infinity where electric potential is zero. Does the electric field change in the region(s) you are integrating over? If so, how does this affect the integration? g40 g) Write down (but do not solve) the integral equation for calculating the electric potential in the region < , starting from infinity where electric potential is zero. Does the electric field change in the region(s) you are integrating over? If so, how does this affect the integration?

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Assume that you have a pipe of radius 0.80m and length 145.00 m, you measure the pressure difference between both ends of the pipe to be 7.00 Pa. If the liquid running through the pipe is water, what is its average velocity? (Provide your result in m/s with 2 decimal places and do not include the units!) The answer 15.17 is incorrect, please explain how to get the correct answer.

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Details Debit Credit Sales 180200 Sales Return 5000 Sales Discount 1200 Purchase 80000 Purchase return and allowances 9500 Purchase discount 2500 Freight on purchase 3300 Salary and wages 11000 Rent 6000 Interest 1200 Office furniture 50000 Inventory 15000 Bills Receivable 13000 Cash and Bank 15000 Rent paid in advance 3000 Bills Payable 9000 Retained Earning 6500 Share Capital 30000 Secured Loan 11000 Accumulated Depreciation 3000 Promotion expenses 3000 Loan and advances 45000 Total 251700 251700

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xample (H.W): calculate the allowable bearing capacity of square driven pile 300×300 mm. The sub soil layers and soil properties are shown in figure below. Use Tomlinson method for clayey soil and Brom's method for sandy soil. F.S = 3. Solution: 6m Sand Ysat. = 18 kN/m³ $\phi$ = 30', k<sub>s</sub> = 1 4m Clay Ysat. = 20 kN/m³ c = 40 kN/m² 1.5m Dense Sand Ysat. = 19 kN/m³ $\phi$ = 40', k<sub>s</sub> = 2

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