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edward morris

edward m.

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A common practice drill that helps roller derby skaters gain strength and endurance is called the pushcart drill. In this drill, several skaters get in a single file line on the track and grab ahold of the waist or shoulders of the skater in front of them. The skater at the back then pushes the entire group around the track. The skaters being pushed do not help by skating themselves; they just allow themselves to roll and hang onto each other. After doing a lap or two, the front skater will fall to the back and become the next person to push the group. Tenacious D., also known as Dawn, is a skater with Madison, Wisconsin's Reservoir Dolls. She is doing the pushcart drill with several of her teammates at one of their team practices. 6 of her teammates are lined up in front of her, ready to be pushed. Her teammates, with all their gear on, have an average mass of 66 kg per person. Dawn wants to know how much power she can generate when pushing her group. She notes that it takes half a lap for the group to reach maximum speed, which she then continues at for the other half of the lap. It takes 11.00 s for her group to reach its maximum speed and another 8 s to complete the lap. One lap around the track is 55 m. The skater hold the waist of the skater standing in the front. The skater at the back pushes the entire team and the skater at the front falls to the back. Process-Oriented Problem 13.006.a - Work done on skaters Dawn does work on the skaters as she accelerates them. On which of the following variables does that work depend? (Check all that apply.) Check All That Apply Dawn's own kinetic energy Dawn's own kinetic energy the total final kinetic energy of the skaters that Dawn is pushing the total final kinetic energy of the skaters that Dawn is pushing the total initial kinetic energy of the skaters that Dawn is pushing the total initial kinetic energy of the skaters that Dawn is pushing the time taken for the skaters to reach their final kinetic energy

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Draw a mechanism and predict the major product for the following reaction: H 1) LIAIH 2) Hâ‚‚O ? Modify the given structure of the starting material to draw the major product. Use the single bond tool to interconvert between double and single bonds. H C N P S H3C F CH CI Br

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The shares of Big Con Plc stand at 110p. Put options with a strike price of 120p are priced at 14p. (i) What is the intrinsic value of the options? [1 mark] (ii) What is the time value of the options? [1 mark] (iii) Explain what might cause the time value to double with no change in intrinsic value? [1 mark] (iv) If the share price fell to 50p by the expiry date, what would be the profit /loss for the holder or the writer of the options? [3 marks] (v) What is the maximum loss for the writer of the option and in what circumstances?

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In an SN2 reaction between bromomethane and hydroxide ion, the concentration of bromoethane is cut in half and the concentration of hydroxide ion is doubled the rate of reaction _____ . Group of answer choices Stays the same Doubles Is cut in half Quadruples

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What QoS (Quality of Service) strategies are implemented within the network architecture of the Organization to prioritize traffic and optimize bandwidth utilization, particularly for real-time applications such as video conferencing and online lectures?

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Key Concept: What is the major source of metabolic acids in the body, and what is its origin?

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5-1-1-4 The isosceles triangular shape with dimensions h = 1m and w = 0.7m is rotating about its hinge point at A. It is rotating at a rate of w = 2 rads, which is decreasing at the constant rate of a = 1 rad/s^2. What angular displacement will have occurred after t = 0.5 seconds? Answer(s): B W

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10.1 Steps 1, 2, 3 (TnomODE, block diagram for torque control of angular velocity Motor torque T. Angular acceleration Angular velocity Load Shown to the right is the motor of Homework 5.16. Om The ODE for the motor's angular velocity is Motor (stator) M=I Izz+bw=Tm=TLood The point of this problem is to choose a motor torque Tm so w ~ wnom (nom is the desired/nominal value of w) even when an unknown load (disturbance) TLoad is applied to the motor. This control system design is separated into four steps (as shown in Chapter 17). 1. Determine Tmnom, the value of Tm that keeps w at nom when TLoad =0. 2. Rewrite the ODE for in terms of, which simplifies choosing a control law for Tm 3. Draw a block diagram that visually depicts this system's mathematics with its control. 4. Choose a control law for Tm (done in Hw 10.2 and Hw 10.3) to minimize the error due to TLovd. 1. Using the fact that wnom is chosen to be a known constant, find Tmnom- Note: One way to find Tmnom is to set Tm = Tmnom = nom, and = nom in the governing ODE. Although Wnom is constant, only minor modifications are needed to treat nom as a specified function of time. Result: Tmnom = 2. To design a control system, Tm is separated into two terms and the ODE is rewritten in terms of where is the error between the actual value of and the desired value of. Express the ODE for in terms of Izz, b, Tm and TLoad Tm=Tmnom+Tm Result: a+a= -nom One way to rewrite the differential equation in terms of, and T. is to substitute = + som. = + nom, and Tm = Tm + Tmnom into the governing equation of motion and then simplify. Note: This step changes the problem of choosing T., so = nom to a problem of choosing T., so = 0. In other words, first choose T,. so the error is driven to zero, then calculate T... = Tnom + T..- Ideally, the control law for Tm is chosen so: The motor quickly gets to its desired angular velocity, which means - nom or [|~| 0. Disturbances such as TLoad have a minimal effect on the motor's angular velocity, i.e. [] is small even with an unknown time-varying TLoad (disturbance). 3. Label the signals, Tm, Tmnom, Tm in this system's block diagram. Nominal control TLoad b b Onom Error control net Plant A block diagram is a picture of the system's mathematics.

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Find the indicated partial derivatives.\ f(x, y) = 8xy^6 + x^8y^8; f_{xxy}, f_{yyy}\ f_{xxy}(x, y) = \ f_{yyy}(x, y) =

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Refrigerant-134a at 1.40 bars and -10°C is compressed by an adiabatic 0.80 kW compressor to a exit state of 7.00 bars and 50°C. Neglecting the changes in kinetic and potential energy, determine: a. the isentropic efficiency of the compressor (%) b. the volume flowrate of the refrigerant at the compressor inlet (litre/s). c. the entropy generation corresponding to the actual operating conditions (kW/K) $\eta_c = \frac{h_{2s} - h_1}{h_2 - h_1}$

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