LAST TWO DIGIT OF ID IS 12
(b) Compute $I_B$, $I_C$, $I_E$, $V_B$ and $V_C$ for the network of Fig.Q2(b). Here, $V_{CC}$= Last two digits of your
student ID+5 and $\alpha$=0.95.
+ $V_{CC}$
8.2k ohm
220k ohm
C2
$I_B$
$V_o$
1 uF
330k ohm
C
$I_C$
Q1
C1
Beta=150
$V_i$
B
1 uF
$I_B$
$\Sigma$
8.2k ohm
$I_E$
0
Fig.Q2(b)