The set of x -intercepts of the function $f(x) = \sqrt{3} + 2\sin x$ on $[0, 2\pi]$ is
$\left\{\frac{4\pi}{3}\right\}$
$\left\{\frac{7\pi}{3}\right\}$
$\left\{\frac{5\pi}{3}, \frac{7\pi}{3}\right\}$
$\left\{\frac{4\pi}{3}, \frac{5\pi}{3}\right\}$
$\left\{\frac{\pi}{3}, \frac{5\pi}{3}\right\}$