A 3.00-kg particle moves from the origin to position (C), having coordinates x=6.50m and y=6.50m as shown in the
figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation
(W=FDelta rcos heta =vec(F)*Delta vec(r)), calculate the work done by the gravitational force in going from O to along the following
paths.
(a) the purple path (OAC)
(b) the red path ( O BC)
]
(c) the blue path C)
]
(d) Your results should all be identical. Whv?
A 3.00-kg particle moves from the origin to position @, having coordinates x = 6.50 m and y = 6.50 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = Fr cos = F . ), calculate the work done by the gravitational force in going from O to @ along the following paths.
y (m)
c x,y
?
x (m) ?
0
(a) the purple path (o
(b) the red path (@) 1
(c) the blue path (o)
(d) Your results should all be identical. Why?