Argon gas in the tank in the above problem was compressed from atmospheric pressure to 1500 psig. This was carried out through a three-stage compression process as follows:
a. Adiabatic compression from atmospheric pressure to 500 psig
b. Isobaric cooling to room temperature (300 K)
c. Adiabatic compression from 500 psig to 1000 psig
d. Isobaric cooling to room temperature (300 K)
e. Adiabatic compression from 1000 psig to 1500 psig
f. Isobaric cooling to room temperature (300 K).
Calculate:
\begin{itemize}
\item The number of moles of argon gas in the tank (use the final state of 1500 psig, 7 m³ and 300 K for this calculation)
\item Work done and heat transferred in each of the six steps (Note: Remember, for an adiabatic process, $PV^\gamma = \text{constant}$, where $\gamma = C_p/C_v$.)
\item Change in internal energy and enthalpy between each intermediate and final states.
\end{itemize}
