Question
Let $h(x) = f(x)g(x)$. If $f(x) = 4x^2 - 3x$ and $g(x) = \ln(3x - 1)$, what is $h'(x)$?
Select the correct answer below:
$h'(x) = (3 - 8x)\ln(3x - 1) + \frac{12x^2 - 9x}{3x}
$h'(x) = (8x - 3)(3x - 1) + \frac{12x^2 - 9x}{3x - 1}
$h'(x) = (8x - 3)\ln(3x - 1) + \frac{4x^2 - 3x}{3x - 1}
$h'(x) = (8x - 3)\ln(3x - 1) + \frac{12x^2 - 9x}{3x - 1}
$h'(x) = (8x - 3)\ln(3x - 1) - \frac{12x^2 - 9x}{3x - 1}